\left\{ \begin{array} { c } { x = 10 } \\ { 3 x + 5 y = 120 } \end{array} \right.
Solve for x, y
x=10
y=18
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3\times 10+5y=120
Consider the second equation. Insert the known values of variables into the equation.
30+5y=120
Multiply 3 and 10 to get 30.
5y=120-30
Subtract 30 from both sides.
5y=90
Subtract 30 from 120 to get 90.
y=\frac{90}{5}
Divide both sides by 5.
y=18
Divide 90 by 5 to get 18.
x=10 y=18
The system is now solved.
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