Solve {c}{4k_{2}+b_{2}=0}{b_{2}=2}

$$\left\{ \begin{array} { c } { 4 k _ { 2 } + b _ { 2 } = 0 } \\ { b _ { 2 } = 2 } \end{array} \right.$$

Solve for k_2, b_2

$$k_{2}=-\frac{1}{2}=-0.5$$

$$b_{2}=2$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$4k_{2}+2=0$$

Subtract 2 from both sides. Anything subtracted from zero gives its negation.

$$4k_{2}=-2$$

Divide both sides by 4.

$$k_{2}=\frac{-2}{4}$$

Reduce the fraction \frac{-2}{4} to lowest terms by extracting and canceling out 2.

$$k_{2}=-\frac{1}{2}$$

The system is now solved.

$$k_{2}=-\frac{1}{2} b_{2}=2$$