\left\{ \begin{array} { c } { - 2 k + b = 5 } \\ { b = 2 } \end{array} \right.
Solve for k, b
k = -\frac{3}{2} = -1\frac{1}{2} = -1.5
b=2
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-2k+2=5
Consider the first equation. Insert the known values of variables into the equation.
-2k=5-2
Subtract 2 from both sides.
-2k=3
Subtract 2 from 5 to get 3.
k=-\frac{3}{2}
Divide both sides by -2.
k=-\frac{3}{2} b=2
The system is now solved.
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