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\lambda ^{2}-2\lambda =0
Subtract 2\lambda from both sides.
\lambda \left(\lambda -2\right)=0
Factor out \lambda .
\lambda =0 \lambda =2
To find equation solutions, solve \lambda =0 and \lambda -2=0.
\lambda ^{2}-2\lambda =0
Subtract 2\lambda from both sides.
\lambda =\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -2 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
\lambda =\frac{-\left(-2\right)±2}{2}
Take the square root of \left(-2\right)^{2}.
\lambda =\frac{2±2}{2}
The opposite of -2 is 2.
\lambda =\frac{4}{2}
Now solve the equation \lambda =\frac{2±2}{2} when ± is plus. Add 2 to 2.
\lambda =2
Divide 4 by 2.
\lambda =\frac{0}{2}
Now solve the equation \lambda =\frac{2±2}{2} when ± is minus. Subtract 2 from 2.
\lambda =0
Divide 0 by 2.
\lambda =2 \lambda =0
The equation is now solved.
\lambda ^{2}-2\lambda =0
Subtract 2\lambda from both sides.
\lambda ^{2}-2\lambda +1=1
Divide -2, the coefficient of the x term, by 2 to get -1. Then add the square of -1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
\left(\lambda -1\right)^{2}=1
Factor \lambda ^{2}-2\lambda +1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(\lambda -1\right)^{2}}=\sqrt{1}
Take the square root of both sides of the equation.
\lambda -1=1 \lambda -1=-1
Simplify.
\lambda =2 \lambda =0
Add 1 to both sides of the equation.