Solve lambda+3y+4z=0

$$\lambda + 3 y + 4 z = 0$$

Solve for y

$$y=\frac{-4z-\lambda }{3}$$

Steps for Solving Linear Equation

Subtract \lambda from both sides. Anything subtracted from zero gives its negation.

$$3y+4z=-\lambda$$

Subtract 4z from both sides.

$$3y=-\lambda -4z$$

The equation is in standard form.

$$3y=-4z-\lambda$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{-4z-\lambda }{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{-4z-\lambda }{3}$$

Solve for z

$$z=\frac{-3y-\lambda }{4}$$

Steps for Solving Linear Equation

Subtract \lambda from both sides. Anything subtracted from zero gives its negation.

$$3y+4z=-\lambda$$

Subtract 3y from both sides.

$$4z=-\lambda -3y$$

The equation is in standard form.

$$4z=-3y-\lambda$$

Divide both sides by 4.

$$\frac{4z}{4}=\frac{-3y-\lambda }{4}$$

Dividing by 4 undoes the multiplication by 4.

$$z=\frac{-3y-\lambda }{4}$$