Solve ∫ (from 4 to 5) of 4x-x^2 wrt x

$$\int_{ 4 }^{ 5 } 4x- { x }^{ 2 } d x$$

Evaluate

$$-\frac{7}{3}\approx -2.333333333$$

Solution Steps

Evaluate the indefinite integral first.

$$\int 4x-x^{2}\mathrm{d}x$$

Integrate the sum term by term.

$$\int 4x\mathrm{d}x+\int -x^{2}\mathrm{d}x$$

Factor out the constant in each of the terms.

$$4\int x\mathrm{d}x-\int x^{2}\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply 4 times \frac{x^{2}}{2}.

$$2x^{2}-\int x^{2}\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply -1 times \frac{x^{3}}{3}.

$$2x^{2}-\frac{x^{3}}{3}$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$2\times 5^{2}-\frac{5^{3}}{3}-\left(2\times 4^{2}-\frac{4^{3}}{3}\right)$$

Simplify.

$$-\frac{7}{3}$$