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\int _{273}^{573}26.78+42.68\times \frac{1}{1000}x-146.4\times 10^{-7}x^{2}\mathrm{d}x
Calculate 10 to the power of -3 and get \frac{1}{1000}.
\int _{273}^{573}26.78+\frac{1067}{25000}x-146.4\times 10^{-7}x^{2}\mathrm{d}x
Multiply 42.68 and \frac{1}{1000} to get \frac{1067}{25000}.
\int _{273}^{573}26.78+\frac{1067}{25000}x-146.4\times \frac{1}{10000000}x^{2}\mathrm{d}x
Calculate 10 to the power of -7 and get \frac{1}{10000000}.
\int _{273}^{573}26.78+\frac{1067}{25000}x-\frac{183}{12500000}x^{2}\mathrm{d}x
Multiply 146.4 and \frac{1}{10000000} to get \frac{183}{12500000}.
\int 26.78+\frac{1067x}{25000}-\frac{183x^{2}}{12500000}\mathrm{d}x
Evaluate the indefinite integral first.
\int 26.78\mathrm{d}x+\int \frac{1067x}{25000}\mathrm{d}x+\int -\frac{183x^{2}}{12500000}\mathrm{d}x
Integrate the sum term by term.
\int 26.78\mathrm{d}x+\frac{1067\int x\mathrm{d}x}{25000}-\frac{183\int x^{2}\mathrm{d}x}{12500000}
Factor out the constant in each of the terms.
\frac{1339x}{50}+\frac{1067\int x\mathrm{d}x}{25000}-\frac{183\int x^{2}\mathrm{d}x}{12500000}
Find the integral of 26.78 using the table of common integrals rule \int a\mathrm{d}x=ax.
\frac{1339x}{50}+\frac{1067x^{2}}{50000}-\frac{183\int x^{2}\mathrm{d}x}{12500000}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply \frac{1067}{25000} times \frac{x^{2}}{2}.
\frac{1339x}{50}+\frac{1067x^{2}}{50000}-\frac{61x^{3}}{12500000}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply -\frac{183}{12500000} times \frac{x^{3}}{3}.
26.78\times 573+\frac{1067}{50000}\times 573^{2}-\frac{61}{12500000}\times 573^{3}-\left(26.78\times 273+\frac{1067}{50000}\times 273^{2}-\frac{61}{12500000}\times 273^{3}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{1578911979}{125000}
Simplify.
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