Evaluate
2\pi \sqrt{2}\approx 8.885765876
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\int \sqrt{2}\mathrm{d}x
Evaluate the indefinite integral first.
\sqrt{2}x
Find the integral of \sqrt{2} using the table of common integrals rule \int a\mathrm{d}x=ax.
2^{\frac{1}{2}}\times 2\pi -2^{\frac{1}{2}}\times 0
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
2\pi \sqrt{2}
Simplify.
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