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\int 1\mathrm{d}x
Evaluate the indefinite integral first.
x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int 1\mathrm{d}x with x.
10050+0
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
10050
Simplify.