Evaluate
-20\sqrt{10}\approx -63.245553203
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\int -3\sqrt{x}\mathrm{d}x
Evaluate the indefinite integral first.
-3\int \sqrt{x}\mathrm{d}x
Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
-2x^{\frac{3}{2}}
Rewrite \sqrt{x} as x^{\frac{1}{2}}. Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{3}{2}}}{\frac{3}{2}}. Simplify. Multiply -3 times \frac{2x^{\frac{3}{2}}}{3}.
-2\times 10^{\frac{3}{2}}+2\times 0^{\frac{3}{2}}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
-20\sqrt{10}
Simplify.
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