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\int 5x^{4}-4\mathrm{d}x
Evaluate the indefinite integral first.
\int 5x^{4}\mathrm{d}x+\int -4\mathrm{d}x
Integrate the sum term by term.
5\int x^{4}\mathrm{d}x+\int -4\mathrm{d}x
Factor out the constant in each of the terms.
x^{5}+\int -4\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{4}\mathrm{d}x with \frac{x^{5}}{5}. Multiply 5 times \frac{x^{5}}{5}.
x^{5}-4x
Find the integral of -4 using the table of common integrals rule \int a\mathrm{d}x=ax.
1^{5}-4-\left(0^{5}-4\times 0\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
-3
Simplify.