Evaluate
\frac{31}{5}=6.2
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\int x^{4}\mathrm{d}x
Evaluate the indefinite integral first.
\frac{x^{5}}{5}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{4}\mathrm{d}x with \frac{x^{5}}{5}.
\frac{\left(-1\right)^{5}}{5}-\frac{\left(-2\right)^{5}}{5}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{31}{5}
Simplify.
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