Solve ∫ int{int{x wrt x}dx}dx

$$\int{ \int{ \int{ x }d x }d x }d x$$

Evaluate

$$Сx^{2}+\frac{x^{4}}{24}+С_{1}x+С_{2}$$

Solution Steps

Simplify.

$$\frac{x^{4}}{24}+2Сx^{2}+Сx$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{x^{4}}{24}+2Сx^{2}+Сx+С$$

Differentiate w.r.t. x

$$\frac{x^{3}}{6}+2Сx+С_{1}$$