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Evaluate
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Differentiate w.r.t. x
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\int \frac{-36}{2+5\times 2}\mathrm{d}x
Subtract 2 from -34 to get -36.
\int \frac{-36}{2+10}\mathrm{d}x
Multiply 5 and 2 to get 10.
\int \frac{-36}{12}\mathrm{d}x
Add 2 and 10 to get 12.
\int -3\mathrm{d}x
Divide -36 by 12 to get -3.
-3x
Find the integral of -3 using the table of common integrals rule \int a\mathrm{d}x=ax.
-3x+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.