Solve ∫ x^99 wrt x=

$$\int x ^ { 99 } d x =$$

Evaluate

$$\frac{x^{100}}{100}+С$$

Solution Steps

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{99}\mathrm{d}x with \frac{x^{100}}{100}.

$$\frac{x^{100}}{100}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{x^{100}}{100}+С$$

Differentiate w.r.t. x

$$x^{99}$$