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Differentiate w.r.t. x
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\int 5x^{9}-3x^{8}\mathrm{d}x
Use the distributive property to multiply x^{8} by 5x-3.
\int 5x^{9}\mathrm{d}x+\int -3x^{8}\mathrm{d}x
Integrate the sum term by term.
5\int x^{9}\mathrm{d}x-3\int x^{8}\mathrm{d}x
Factor out the constant in each of the terms.
\frac{x^{10}}{2}-3\int x^{8}\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{9}\mathrm{d}x with \frac{x^{10}}{10}. Multiply 5 times \frac{x^{10}}{10}.
\frac{x^{10}}{2}-\frac{x^{9}}{3}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{8}\mathrm{d}x with \frac{x^{9}}{9}. Multiply -3 times \frac{x^{9}}{9}.
\frac{x^{10}}{2}-\frac{x^{9}}{3}+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.