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Differentiate w.r.t. x
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\int x^{14}\mathrm{d}x
To multiply powers of the same base, add their exponents. Add 4 and 10 to get 14.
\frac{x^{15}}{15}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{14}\mathrm{d}x with \frac{x^{15}}{15}.
\frac{x^{15}}{15}+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.