Evaluate
\frac{b^{3}}{3}+С
Differentiate w.r.t. b
b^{2}
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\frac{b^{3}}{3}
Since \int b^{k}\mathrm{d}b=\frac{b^{k+1}}{k+1} for k\neq -1, replace \int b^{2}\mathrm{d}b with \frac{b^{3}}{3}.
\frac{b^{3}}{3}+С
If F\left(b\right) is an antiderivative of f\left(b\right), then the set of all antiderivatives of f\left(b\right) is given by F\left(b\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
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