Evaluate
\frac{93\left(1-n\right)}{n+1}
Differentiate w.r.t. n
-\frac{186}{\left(n+1\right)^{2}}
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\int \frac{1-n}{n+1}\mathrm{d}x
Evaluate the indefinite integral first.
\frac{1-n}{n+1}x
Find the integral of \frac{1-n}{n+1} using the table of common integrals rule \int a\mathrm{d}x=ax.
\frac{\left(1-n\right)x}{n+1}
Simplify.
\left(1-n\right)\left(n+1\right)^{-1}\times 100-\left(1-n\right)\left(n+1\right)^{-1}\times 7
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{93\left(1-n\right)}{n+1}
Simplify.
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