Evaluate
2\sin(\frac{1}{2})\sin(\frac{13}{2})\approx 0.206268032
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\int \sin(u)\mathrm{d}u
Evaluate the indefinite integral first.
-\cos(u)
Use \int \sin(u)\mathrm{d}u=-\cos(u) from the table of common integrals to obtain the result.
-\cos(7)+\cos(6)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
2\sin(\frac{13}{2})\sin(\frac{1}{2})
Simplify.
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