Evaluate
\ln(\frac{25}{23})\approx 0.083381609
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\int \frac{1}{f}\mathrm{d}f
Evaluate the indefinite integral first.
\ln(|f|)
Use \int \frac{1}{f}\mathrm{d}f=\ln(|f|) from the table of common integrals to obtain the result.
\ln(|25|)-\ln(|23|)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\ln(\frac{25}{23})
Simplify.
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