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\int \frac{1}{\sqrt[5]{x^{4}}}\mathrm{d}x
Evaluate the indefinite integral first.
5\sqrt[5]{x}
Rewrite \frac{1}{x^{\frac{4}{5}}} as x^{-\frac{4}{5}}. Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{-\frac{4}{5}}\mathrm{d}x with \frac{x^{\frac{1}{5}}}{\frac{1}{5}}. Simplify and convert from exponential to radical form.
5\times 80^{\frac{1}{5}}-5\times 10^{\frac{1}{5}}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
5\sqrt[5]{80}-5\sqrt[5]{10}
Simplify.