Evaluate
2\sin(\frac{7}{2})\sin(\frac{9}{2})\approx 0.68580234
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\int \sin(x)\mathrm{d}x
Evaluate the indefinite integral first.
-\cos(x)
Use \int \sin(x)\mathrm{d}x=-\cos(x) from the table of common integrals to obtain the result.
-\cos(8)+\cos(1)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
2\sin(\frac{9}{2})\sin(\frac{7}{2})
Simplify.
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