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\int 5\sqrt[4]{x}\mathrm{d}x
Evaluate the indefinite integral first.
5\int \sqrt[4]{x}\mathrm{d}x
Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
4x^{\frac{5}{4}}
Rewrite \sqrt[4]{x} as x^{\frac{1}{4}}. Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{1}{4}}\mathrm{d}x with \frac{x^{\frac{5}{4}}}{\frac{5}{4}}. Simplify. Multiply 5 times \frac{4x^{\frac{5}{4}}}{5}.
4\times 4^{\frac{5}{4}}-4\times 1^{\frac{5}{4}}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
16\sqrt{2}-4
Simplify.