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Differentiate w.r.t. y
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\int \sqrt{1-\frac{24\sqrt{y}-1}{4y}+36}\mathrm{d}x
Evaluate the indefinite integral first.
\sqrt{1-\frac{24\sqrt{y}-1}{4y}+36}x
Find the integral of \sqrt{1-\frac{24\sqrt{y}-1}{4y}+36} using the table of common integrals rule \int a\mathrm{d}x=ax.
\frac{\sqrt{148-\frac{24}{\sqrt{y}}+\frac{1}{y}}x}{2}
Simplify.
\frac{1}{2}\left(148-24y^{-\frac{1}{2}}+y^{-1}\right)^{\frac{1}{2}}\times 4-\frac{1}{2}\left(148-24y^{-\frac{1}{2}}+y^{-1}\right)^{\frac{1}{2}}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{3\sqrt{148y-24\sqrt{y}+1}}{2\sqrt{y}}
Simplify.