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\int 3x^{2}-x+1\mathrm{d}x
Evaluate the indefinite integral first.
\int 3x^{2}\mathrm{d}x+\int -x\mathrm{d}x+\int 1\mathrm{d}x
Integrate the sum term by term.
3\int x^{2}\mathrm{d}x-\int x\mathrm{d}x+\int 1\mathrm{d}x
Factor out the constant in each of the terms.
x^{3}-\int x\mathrm{d}x+\int 1\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply 3 times \frac{x^{3}}{3}.
x^{3}-\frac{x^{2}}{2}+\int 1\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply -1 times \frac{x^{2}}{2}.
x^{3}-\frac{x^{2}}{2}+x
Find the integral of 1 using the table of common integrals rule \int a\mathrm{d}x=ax.
3^{3}-\frac{3^{2}}{2}+3-\left(1^{3}-\frac{1^{2}}{2}+1\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
24
Simplify.
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