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Differentiate w.r.t. n
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\int 2n-1\mathrm{d}x
Evaluate the indefinite integral first.
\left(2n-1\right)x
Find the integral of 2n-1 using the table of common integrals rule \int a\mathrm{d}x=ax.
\left(2n-1\right)\times 2-\left(2n-1\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
2n-1
Simplify.