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\int x+9\mathrm{d}x
Evaluate the indefinite integral first.
\int x\mathrm{d}x+\int 9\mathrm{d}x
Integrate the sum term by term.
\frac{x^{2}}{2}+\int 9\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}.
\frac{x^{2}}{2}+9x
Find the integral of 9 using the table of common integrals rule \int a\mathrm{d}x=ax.
\frac{2^{2}}{2}+9\times 2-\left(\frac{1^{2}}{2}+9\times 1\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{21}{2}
Simplify.