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\int 3x^{2}-2x\mathrm{d}x
Evaluate the indefinite integral first.
\int 3x^{2}\mathrm{d}x+\int -2x\mathrm{d}x
Integrate the sum term by term.
3\int x^{2}\mathrm{d}x-2\int x\mathrm{d}x
Factor out the constant in each of the terms.
x^{3}-2\int x\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply 3 times \frac{x^{3}}{3}.
x^{3}-x^{2}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply -2 times \frac{x^{2}}{2}.
2^{3}-2^{2}-\left(1^{3}-1^{2}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
4
Simplify.