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Differentiate w.r.t. a
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\int a\sin(t)r^{2}\mathrm{d}t
Evaluate the indefinite integral first.
ar^{2}\int \sin(t)\mathrm{d}t
Factor out the constant using \int af\left(t\right)\mathrm{d}t=a\int f\left(t\right)\mathrm{d}t.
-ar^{2}\cos(t)
Use \int \sin(a)\mathrm{d}a=-\cos(a) from the table of common integrals to obtain the result.
-ar^{2}\cos(\frac{15}{2})+ar^{2}\cos(1)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
a\left(-\cos(\frac{15}{2})+\cos(1)\right)r^{2}
Simplify.