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\int \frac{1}{x}-3\mathrm{d}x
Evaluate the indefinite integral first.
\int \frac{1}{x}\mathrm{d}x+\int -3\mathrm{d}x
Integrate the sum term by term.
\ln(|x|)+\int -3\mathrm{d}x
Use \int \frac{1}{x}\mathrm{d}x=\ln(|x|) from the table of common integrals to obtain the result.
\ln(|x|)-3x
Find the integral of -3 using the table of common integrals rule \int a\mathrm{d}x=ax.
\ln(|4|)-3\times 4-\left(\ln(|\frac{1}{4}|)-3\times \frac{1}{4}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
4\ln(2)-\frac{45}{4}
Simplify.