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Differentiate w.r.t. x
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\int _{0}^{x}t^{2}\phi \mathrm{d}t
Multiply t and t to get t^{2}.
\int t^{2}\phi \mathrm{d}t
Evaluate the indefinite integral first.
\phi \int t^{2}\mathrm{d}t
Factor out the constant using \int af\left(t\right)\mathrm{d}t=a\int f\left(t\right)\mathrm{d}t.
\phi \times \frac{t^{3}}{3}
Since \int t^{k}\mathrm{d}t=\frac{t^{k+1}}{k+1} for k\neq -1, replace \int t^{2}\mathrm{d}t with \frac{t^{3}}{3}.
\frac{\phi t^{3}}{3}
Simplify.
\frac{1}{3}\phi x^{3}-\frac{1}{3}\phi \times 0^{3}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{\phi x^{3}}{3}
Simplify.