Solve ∫ (from 0 to x) of (x+2y) wrt y=

$$\int _ { 0 } ^ { x } ( x + 2 y ) d y =$$

Evaluate

$$2x^{2}$$

Solution Steps

Evaluate the indefinite integral first.

$$\int x+2y\mathrm{d}y$$

Integrate the sum term by term.

$$\int x\mathrm{d}y+\int 2y\mathrm{d}y$$

Factor out the constant in each of the terms.

$$\int x\mathrm{d}y+2\int y\mathrm{d}y$$

Find the integral of x using the table of common integrals rule \int a\mathrm{d}y=ay.

$$xy+2\int y\mathrm{d}y$$

Since \int y^{k}\mathrm{d}y=\frac{y^{k+1}}{k+1} for k\neq -1, replace \int y\mathrm{d}y with \frac{y^{2}}{2}. Multiply 2 times \frac{y^{2}}{2}.

$$xy+y^{2}$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$xx+x^{2}-\left(x\times 0+0^{2}\right)$$

Simplify.

$$2x^{2}$$

Differentiate w.r.t. x

$$4x$$