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Differentiate w.r.t. p
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\int _{0}^{t}ex^{2}pa\mathrm{d}x
Multiply x and x to get x^{2}.
\int ex^{2}pa\mathrm{d}x
Evaluate the indefinite integral first.
epa\int x^{2}\mathrm{d}x
Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
epa\times \frac{x^{3}}{3}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}.
\frac{epax^{3}}{3}
Simplify.
\frac{1}{3}epat^{3}-\frac{1}{3}epa\times 0^{3}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{epat^{3}}{3}
Simplify.