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Differentiate w.r.t. a
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\int -3x^{2}+3\mathrm{d}x
Evaluate the indefinite integral first.
\int -3x^{2}\mathrm{d}x+\int 3\mathrm{d}x
Integrate the sum term by term.
-3\int x^{2}\mathrm{d}x+\int 3\mathrm{d}x
Factor out the constant in each of the terms.
-x^{3}+\int 3\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply -3 times \frac{x^{3}}{3}.
-x^{3}+3x
Find the integral of 3 using the table of common integrals rule \int a\mathrm{d}x=ax.
-a^{3}+3a-\left(-0^{3}+3\times 0\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
a\left(-a^{2}+3\right)
Simplify.