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\int e^{2\sqrt{2\pi +1}}\mathrm{d}x
Evaluate the indefinite integral first.
e^{2\sqrt{2\pi +1}}x
Find the integral of e^{2\sqrt{2\pi +1}} using the table of common integrals rule \int a\mathrm{d}x=ax.
e^{2\left(2\pi +1\right)^{\frac{1}{2}}}\times 4-e^{2\left(2\pi +1\right)^{\frac{1}{2}}}\times 0
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
4e^{2\sqrt{2\pi +1}}
Simplify.