Evaluate
\frac{64}{3}\approx 21.333333333
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\int c^{2}\mathrm{d}c
Evaluate the indefinite integral first.
\frac{c^{3}}{3}
Since \int c^{k}\mathrm{d}c=\frac{c^{k+1}}{k+1} for k\neq -1, replace \int c^{2}\mathrm{d}c with \frac{c^{3}}{3}.
\frac{4^{3}}{3}-\frac{0^{3}}{3}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{64}{3}
Simplify.
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