Evaluate
-9
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\int 2x-6\mathrm{d}x
Evaluate the indefinite integral first.
\int 2x\mathrm{d}x+\int -6\mathrm{d}x
Integrate the sum term by term.
2\int x\mathrm{d}x+\int -6\mathrm{d}x
Factor out the constant in each of the terms.
x^{2}+\int -6\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply 2 times \frac{x^{2}}{2}.
x^{2}-6x
Find the integral of -6 using the table of common integrals rule \int a\mathrm{d}x=ax.
3^{2}-6\times 3-\left(0^{2}-6\times 0\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
-9
Simplify.
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