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16000
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\int 80y\mathrm{d}y
Evaluate the indefinite integral first.
80\int y\mathrm{d}y
Factor out the constant using \int af\left(y\right)\mathrm{d}y=a\int f\left(y\right)\mathrm{d}y.
40y^{2}
Since \int y^{k}\mathrm{d}y=\frac{y^{k+1}}{k+1} for k\neq -1, replace \int y\mathrm{d}y with \frac{y^{2}}{2}. Multiply 80 times \frac{y^{2}}{2}.
40\times 20^{2}-40\times 0^{2}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
16000
Simplify.
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