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\int 3x-\cos(x)\mathrm{d}x
Evaluate the indefinite integral first.
\int 3x\mathrm{d}x+\int -\cos(x)\mathrm{d}x
Integrate the sum term by term.
3\int x\mathrm{d}x-\int \cos(x)\mathrm{d}x
Factor out the constant in each of the terms.
\frac{3x^{2}}{2}-\int \cos(x)\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply 3 times \frac{x^{2}}{2}.
\frac{3x^{2}}{2}-\sin(x)
Use \int \cos(x)\mathrm{d}x=\sin(x) from the table of common integrals to obtain the result.
\frac{3}{2}\times 2^{2}-\sin(2)-\left(\frac{3}{2}\times 0^{2}-\sin(0)\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
6-\sin(2)
Simplify.