Evaluate
\frac{1}{4}=0.25
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\int y^{3}\mathrm{d}y
Evaluate the indefinite integral first.
\frac{y^{4}}{4}
Since \int y^{k}\mathrm{d}y=\frac{y^{k+1}}{k+1} for k\neq -1, replace \int y^{3}\mathrm{d}y with \frac{y^{4}}{4}.
\frac{1^{4}}{4}-\frac{0^{4}}{4}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{1}{4}
Simplify.
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