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\int \int _{0}^{t}e^{k}\mathrm{d}k\mathrm{d}t
Evaluate the indefinite integral first.
e^{t}-t
Simplify.
e^{1}-1-\left(e^{0}-0\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
e-2
Simplify.