Solve ∫ (from 0 to 1) of 1/2sqrt{x wrt x

$$\int _ { 0 } ^ { 1 } \frac { 1 } { 2 } \sqrt { x } d x$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

Evaluate the indefinite integral first.

$$\int \frac{\sqrt{x}}{2}\mathrm{d}x$$

Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$\frac{\int \sqrt{x}\mathrm{d}x}{2}$$

Rewrite \sqrt{x} as x^{\frac{1}{2}}. Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{3}{2}}}{\frac{3}{2}}. Simplify.

$$\frac{x^{\frac{3}{2}}}{3}$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$\frac{1^{\frac{3}{2}}}{3}-\frac{0^{\frac{3}{2}}}{3}$$

Simplify.

$$\frac{1}{3}$$