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\int \sqrt{e-1}\mathrm{d}x
Evaluate the indefinite integral first.
\sqrt{e-1}x
Find the integral of \sqrt{e-1} using the table of common integrals rule \int a\mathrm{d}x=ax.
\left(e-1\right)^{\frac{1}{2}}\ln(2)\ln(e)^{-1}-\left(e-1\right)^{\frac{1}{2}}\times 0
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\sqrt{e-1}\ln(2)
Simplify.