Solve ∫ (from - 2 to 2) of (3x^2-4x+5) wrt x

$$\int _ { - 2 } ^ { 2 } ( 3 x ^ { 2 } - 4 x + 5 ) d x$$

Evaluate

$$36$$

Solution Steps

Evaluate the indefinite integral first.

$$\int 3x^{2}-4x+5\mathrm{d}x$$

Integrate the sum term by term.

$$\int 3x^{2}\mathrm{d}x+\int -4x\mathrm{d}x+\int 5\mathrm{d}x$$

Factor out the constant in each of the terms.

$$3\int x^{2}\mathrm{d}x-4\int x\mathrm{d}x+\int 5\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply 3 times \frac{x^{3}}{3}.

$$x^{3}-4\int x\mathrm{d}x+\int 5\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply -4 times \frac{x^{2}}{2}.

$$x^{3}-2x^{2}+\int 5\mathrm{d}x$$

Find the integral of 5 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$x^{3}-2x^{2}+5x$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$2^{3}-2\times 2^{2}+5\times 2-\left(\left(-2\right)^{3}-2\left(-2\right)^{2}+5\left(-2\right)\right)$$

Simplify.

$$36$$