Solve ∫ (from - 2 to 0) of (3x^2-x) wrt x

$$\int _ { - 2 } ^ { 0 } ( 3 x ^ { 2 } - x ) d x$$

Evaluate

$$10$$

Solution Steps

Evaluate the indefinite integral first.

$$\int 3x^{2}-x\mathrm{d}x$$

Integrate the sum term by term.

$$\int 3x^{2}\mathrm{d}x+\int -x\mathrm{d}x$$

Factor out the constant in each of the terms.

$$3\int x^{2}\mathrm{d}x-\int x\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply 3 times \frac{x^{3}}{3}.

$$x^{3}-\int x\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply -1 times \frac{x^{2}}{2}.

$$x^{3}-\frac{x^{2}}{2}$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$0^{3}-\frac{0^{2}}{2}-\left(\left(-2\right)^{3}-\frac{\left(-2\right)^{2}}{2}\right)$$

Simplify.

$$10$$