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Differentiate w.r.t. m
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\int |m|+|m-1|+|m-2|\mathrm{d}x
Evaluate the indefinite integral first.
\left(|m|+|m-1|+|m-2|\right)x
Find the integral of |m|+|m-1|+|m-2| using the table of common integrals rule \int a\mathrm{d}x=ax.
\left(|m|+|m-1|+|m-2|\right)\times 4-\left(|m|+|m-1|+|m-2|\right)\left(-1\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
5|m-1|+5|m|+5|m-2|
Simplify.