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Solve for F
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\int _{-1}^{2}1\mathrm{d}x=3F
Combine F\times 2 and -F\left(-1\right) to get 3F.
3F=\int _{-1}^{2}1\mathrm{d}x
Swap sides so that all variable terms are on the left hand side.
3F=3
The equation is in standard form.
\frac{3F}{3}=\frac{3}{3}
Divide both sides by 3.
F=\frac{3}{3}
Dividing by 3 undoes the multiplication by 3.
F=1
Divide 3 by 3.