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Differentiate w.r.t. S
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\int x^{2}+x\mathrm{d}x
Evaluate the indefinite integral first.
\int x^{2}\mathrm{d}x+\int x\mathrm{d}x
Integrate the sum term by term.
\frac{x^{3}}{3}+\int x\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}.
\frac{x^{3}}{3}+\frac{x^{2}}{2}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}.
\frac{3^{3}}{3}+\frac{3^{2}}{2}-\left(\frac{1}{3}\left(Scanneld\right)^{3}+\frac{1}{2}\left(Scanneld\right)^{2}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{27}{2}-\frac{a^{2}e^{2}\left(2Scean^{2}ld+3\right)S^{2}c^{2}n^{4}l^{2}d^{2}}{6}
Simplify.