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\int \sin(x)+\cos(x)\mathrm{d}x
Evaluate the indefinite integral first.
\int \sin(x)\mathrm{d}x+\int \cos(x)\mathrm{d}x
Integrate the sum term by term.
-\cos(x)+\int \cos(x)\mathrm{d}x
Use \int \sin(x)\mathrm{d}x=-\cos(x) from the table of common integrals to obtain the result.
-\cos(x)+\sin(x)
Use \int \cos(x)\mathrm{d}x=\sin(x) from the table of common integrals to obtain the result.
-\cos(1.3\pi )+\sin(1.3\pi )-\left(-\cos(\pi )+\sin(\pi )\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{\sqrt{2\sqrt{5}-2}\sqrt[4]{5}-5-\sqrt{5}}{4}
Simplify.